Link to video if needed speaker converts x=250 to z=1.67 using the z-score formula. Using the z-table in the back of the book he determines P(X>250) = .0475. If you used the NORMALCDF, what would your answer be taken 5 decimal places (the answer is slightly different)?

The speaker determines P(250<x<350) = .0475 by using the complement rule, etc. We understand that 250 and 350 are the boundaries. Again, using NORMALCDF what would your answer be taking 5 decimal places.The speaker states he needs to find “x” based on given the Probability, “the bottom 5%” based on 95% probability. The speaker calculates 150.5. In my lecture video, I refer to this as INVNORM, where we are doing the opposite of what we have already done (before we were given x and were finding the probability. Now we have the probability (95%) and need to find x – in essence going backward). Take your INVNORM answer 2 decimal places.FIND :1) P(X>250) = answer should be 5 decimal places using NORMALCDF.2) P(250<x<350) = answer should be 5 decimal places. using NORMALCDF3) Given the “bottom 5% what is the value of x must take 2 decimal places?